Class 9

Class 9 Physics Assignment Answer 2022 (6th Week)

As per the introduction of the Bangladesh Education Board, every class except the SSC and HSC candidates have to submit assignments as their final evaluation. Today, we will discuss Class 9 Physics Assignment Answer. Physics is a compulsory subject for the students of science and a bit complicated also. Many students of class 9 are finding it challenging to complete their Physics Assignment. So, most welcome you to our website to get the best and proper answer.

Class 9 Physics Assignment Answer 2022

The students of class nine often find difficulties in physics. As it is a bit complicated subject, students who not much sincere are usually made mistakes. Physics is considered one of the most exciting subjects in the world only if you can able to remember the laws and formulas correctly. However, for your convenience, we have solved your assignment and provided the answer for you.

Another thing is that physics is co-related vastly with higher mathematics. You have to have a good command over math subject as well. The most important thing that all students must remember is to be sincere while doing the Class 9 Physics Assignment Answer.

Class 9 Physics Assignment Answer 6th Week

We have provided the accurate Class 9 Physics Assignment Answer on our website here. There were two assignments of physics of class 9, and the 3rd one has already been assigned. The assignment and the answer are given in the PDF file. If you want to get the assignment answer, you need to open the PDF file first. After downloading the file, you can open it.

https://i1.wp.com/i.imgur.com/ulYJ2nJ.jpg?w=708&ssl=1

āĻ…ā§āϝāĻžāϏāĻžāχāύāĻŽā§‡āĻ¨ā§āϟ āĻŦāĻž āύāĻŋāĻ°ā§āϧāĻžāϰāĻŋāϤ āĻ•āĻžāϜ :

āύāĻŋāĻ°ā§āĻĻ⧇āĻļāύāĻž :
āύāĻŦāĻŽ āĻļā§āϰ⧇āĻŖā§€āϰ āĻĒāĻĻāĻžāĻ°ā§āĻĨ āĻŦāĻŋāĻœā§āĻžāĻžāύ āĻŦāχāϝāĻŧ⧇āϰ ā§¨ā§Š āύāĻ‚ āĻĒ⧃āĻˇā§āĻ āĻžāϰ āĻ•āĻžāĻœā§‡āϰ āϧāĻžāϰāĻž āĻ…āύ⧁āϏāϰāĻŖ āĻ•āϰāĻŦ⧇āύāĨ¤ āϏāĻŽā§āĻ­āĻŦ āĻšāϞ⧇ āχāωāϟāĻŋāωāĻŦ āĻāϰ āϏāĻžāĻšāĻžāĻ¯ā§āϝ āύāĻŋāĻŦ⧇āĨ¤

āύāĻŦāĻŽ āĻļā§āϰ⧇āĻŖā§€āϰ āώāĻˇā§āĻ  āϏāĻĒā§āϤāĻžāĻšā§‡āϰ āĻĒāĻĻāĻžāĻ°ā§āĻĨāĻŦāĻŋāĻœā§āĻžāĻžāύ āĻ…ā§āϝāĻžāϏāĻžāχāύāĻŽā§‡āĻ¨ā§āϟ āϏāĻŽāĻžāϧāĻžāύ

āĻ•āĻžāĻœā§‡āϰ āϧāĻžāϰāĻž :

āĻ¸ā§āϞāĻžāχāĻĄ āĻ•ā§āϝāĻžāϞāĻŋāĻĒāĻžāĻ°ā§āϏāϟāĻŋ āύāĻŋā§Ÿā§‡ āĻāϰ āĻĒā§āϰāϧāĻžāύ āĻ¸ā§āϕ⧇āϞ⧇āϰ āĻ•ā§āώ⧁āĻĻā§āϰāϤāĻŽ āĻāĻ• āĻ­āĻžāϗ⧇āϰ āĻŽāĻžāύ āĻāĻŦāĻ‚ āĻ­āĻžāĻ°ā§āύāĻŋāϝāĻŧāĻžāϰ āĻ¸ā§āϕ⧇āϞ⧇āϰ āĻŽā§‹āϟ āϏāĻ‚āĻ–ā§āϝāĻž āĻ•āϤ āϤāĻž āϞāĻ•ā§āĻˇā§āϝ āĻ•āϰāĻŋāĨ¤ āĻāϰāĻĒāϰ āϝāĻ¨ā§āĻ¤ā§āϰāϟāĻŋāϰ āĻ­āĻžāĻ°ā§āύāĻŋāϝāĻŧāĻžāϰ āĻ§ā§āϰ⧁āĻŦāĻ• (VC) āĻŦ⧇āϰ āĻ•āϰāĻŋāĨ¤

āĻāĻ–āύ āĻŽāĻžāĻ°ā§āĻŦ⧇āϞāϟāĻŋāϰ āĻŦā§āϝāĻžāϏ āĻŦāϰāĻžāĻŦāϰ āĻ¸ā§āϞāĻžāχāĻĄ āĻ•ā§āϝāĻžāϞāĻŋāĻĒāĻžāĻ°ā§āϏ⧇āϰ āĻĻ⧁āχ āĻšā§‹āϝāĻŧāĻžāϞ⧇āϰ āĻŽāĻ§ā§āϝ⧇ āĻ¸ā§āĻĨāĻžāĻĒāύ āĻ•āϰ⧇ āĻšā§‹āϝāĻŧāĻžāϞ āĻĻ⧁āϟāĻŋāϕ⧇ āĻŦāĻ¸ā§āϤ⧁āϰ āĻĻ⧁āχ āĻĒā§āϰāĻžāĻ¨ā§āϤ⧇āϰ āϏāĻžāĻĨ⧇ āĻ¸ā§āĻĒāĻ°ā§āĻļ āĻ•āϰāĻŋāĨ¤ āĻāχ āĻ…āĻŦāĻ¸ā§āĻĨāĻžāϝāĻŧ āĻ­āĻžāĻ°ā§āύāĻŋāϝāĻŧāĻžāϰ⧇āϰ āĻļā§‚āĻ¨ā§āϝ āĻĻāĻžāĻ— āĻĒā§āϰāϧāĻžāύ āĻ¸ā§āϕ⧇āϞ⧇āϰ āϝ⧇ āĻĻāĻžāĻ— āĻ…āϤāĻŋāĻ•ā§āϰāĻŽ āĻ•āϰ⧇, āϏ⧇āχ āĻĻāĻžāϗ⧇āϰ āĻĒāĻžāĻ āχ āĻšāϞ āĻĒā§āϰāϧāĻžāύ āĻ¸ā§āϕ⧇āϞ āĻĒāĻžāĻ  M āύāĻŋāĻ°ā§āĻŖāϝāĻŧ āĻ•āϰāĻŋāĨ¤

āĻāχ āĻ…āĻŦāĻ¸ā§āĻĨāĻžāϝāĻŧ āĻ­āĻžāĻ°ā§āύāĻŋ⧟āĻžāϰ⧇āϰ āĻ•āϤ āϏāĻ‚āĻ–ā§āϝāĻ• āĻĻāĻžāĻ— āĻĒā§āϰāϧāĻžāύ āĻ¸ā§āϕ⧇āϞ āĻāϰ āϝ⧇āϕ⧋āύ⧋ āĻāĻ•āϟāĻŋ āĻĻāĻžāϗ⧇āϰ āϏāĻžāĻĨ⧇ āĻŽāĻŋāϞ⧇ āϝāĻžāϝāĻŧ āϤāĻž āύāĻŋāĻ°ā§āĻŖāϝāĻŧ āĻ•āϰāĻž āĻšāϞ⧋āĨ¤ āĻāϟāĻŋ āĻ­āĻžāĻ°ā§āύāĻŋāϝāĻŧāĻžāϰ āϏāĻŽāĻĒāĻžāϤāύ VāĨ¤

āĻĒā§āϰāϝāĻŧā§‹āϜāύ⧀āϝāĻŧ āĻšāĻŋāϏāĻžāĻŦ⧇āϰ āϏāĻžāĻšāĻžāĻ¯ā§āϝ⧇ āĻŽāĻžāĻ°ā§āĻŦ⧇āϞ⧇āϰ āĻŦā§āϝāĻžāϏāĻžāĻ°ā§āϧ, āφāϝāĻŧāϤāύ āύāĻŋāĻ°ā§āĻŖāϝāĻŧ āĻ•āϰāĻŋāĨ¤

āĻšāĻŋāϏāĻžāĻŦ :

āĻŽāĻžāĻ°ā§āĻŦ⧇āϞ⧇āϰ āĻŦā§āϝāĻžāϏ āĻĒāϰāĻŋāĻŽāĻžāĻĒ⧇āϰ āĻ•ā§āώ⧇āĻ¤ā§āϰ⧇,
āĻŽā§‚āϞ āĻ¸ā§āϕ⧇āϞ⧇āϰ āĻĒāĻžāĻ , M =1.7 inch
āĻ­āĻžāĻ°ā§āύāĻŋāϝāĻŧāĻžāϰ āϏāĻŽāĻĒāĻžāϤāύ, V = 8
āĻ­āĻžāĻ°ā§āύāĻŋāϝāĻŧāĻžāϰ āĻ§ā§āϰ⧁āĻŦāĻ•, VC = āĻŽā§‚āϞ āĻ¸ā§āϕ⧇āϞ⧇āϰ āĻ•ā§āώ⧁āĻĻā§āϰāϤāĻŽ ā§§ āĻ­āĻžāϗ⧇āϰ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ Ãˇ āĻ­āĻžāĻ°ā§āύāĻŋāϝāĻŧāĻžāϰ āĻ¸ā§āϕ⧇āϞ⧇āϰ āĻ­āĻžāĻ— āϏāĻ‚āĻ–ā§āϝāĻž

= 0.1 inch Ãˇ 10
= 0.01 inch
āĻŽāĻžāĻ°ā§āĻŦ⧇āϞāϟāĻŋāϰ āĻŦā§āϝāĻžāϏ, L = M+V×VC
= 1.7+8×0.01
=1.78 inch
āφāĻŦāĻžāϰ,
1 inch =2.54 cm
1.78 inch =(2.54×1.78) cm = 4.52 cm
āϏ⧁āϤāϰāĻžāĻ‚, āĻŽāĻžāĻ°ā§āĻŦ⧇āϞāϟāĻŋāϰ āĻŦā§āϝāĻžāϏ = 4.52 cm
āϤāĻžāĻšāϞ⧇ āĻŽāĻžāĻ°ā§āĻŦ⧇āϞāϟāĻŋāϰ āĻŦā§āϝāĻžāϏāĻžāĻ°ā§āϧ = 4.52Ãˇ2 cm
= 2.26 cm
āĻŽāĻžāĻ°ā§āĻŦ⧇āϞāϟāĻŋāϰ āφāϝāĻŧāϤāύ = 4/3Ī€ R^3
= 4/3 × 3.1416 × (2.26)^3
= 48.35 cm^3
āĻŽāĻžāĻ°ā§āĻŦ⧇āϞāϟāĻŋāϰ āĻĒāϰāĻŋāĻŽāĻžāĻĒ āĻ•āϰāĻž āφāϝāĻŧāϤāύ = 48.35 cm^3

āϝ⧇āĻšā§‡āϤ⧁ āĻŽāĻžāĻ°ā§āĻŦ⧇āϞāϟāĻŋāϰ āφāĻĒ⧇āĻ•ā§āώāĻŋāĻ• āĻ¤ā§āϰ⧁āϟāĻŋ 10% āĻ•āĻžāĻœā§‡āχ āĻŽāĻžāĻ°ā§āĻŦ⧇āϞāϟāĻŋāϰ āĻŦā§āϝāĻžāϏāĻžāĻ°ā§āϧ āĻĒāϰāĻŋāĻŽāĻžāĻĒ āĻ•āϰāĻž āĻšāϞ⧇ āϏāĻŦāĻšā§‡āϝāĻŧ⧇ āĻ•āĻŽ 2.034 cm āĻāĻŦāĻ‚ āϏāĻŦāĻšā§‡āϝāĻŧ⧇ āĻŦ⧇āĻļāĻŋ 2.48 cm āĻšāϤ⧇ āĻĒāĻžāϰ⧇āĨ¤

āĻ•āĻžāĻœā§‡āχ āφāϝāĻŧāϤāύ,
āϏāĻŦāĻšā§‡āϝāĻŧ⧇ āĻ•āĻŽ = 4/3Ī€ R^3
= 4/3 × 3.1416 × (2.034)^3
= 35.24 cm^3
āĻāĻŦāĻ‚ āϏāĻŦāĻšā§‡āϝāĻŧ⧇ āĻŦ⧇āĻļāĻŋ = 4/3Ī€ R^3
= 4/3 × 3.1416 × (2.48)^3
= 63.89 cm^3 āĻšāϤ⧇ āĻĒāĻžāϰ⧇āĨ¤

āĻ•āĻžāĻœā§‡āχ āĻšā§‚āĻĄāĻŧāĻžāĻ¨ā§āϤ āĻ¤ā§āϰ⧁āϟāĻŋ –
|48.35 – 35.24| = 13.11 cm^3
āĻ…āĻĨāĻŦāĻž, |63.89 – 48.35| = 15.54 cm^3

āϝ⧇āĻšā§‡āϤ⧁ āĻĻ⧁āϟāĻŋ āϏāĻŽāĻžāύ āύāϝāĻŧ āφāĻŽāϰāĻž āĻŦāĻĄāĻŧāϟāĻŋ āύāĻŋāχāĨ¤ āĻ…āĻ°ā§āĻĨāĻžā§Ž āĻšā§‚āĻĄāĻŧāĻžāĻ¨ā§āϤ āĻ¤ā§āϰ⧁āϟāĻŋ 15.54 cm^3
āĻ•āĻžāĻœā§‡āχ āφāϝāĻŧāϤāύ āĻĒāϰāĻŋāĻŽāĻžāĻĒ⧇āϰ āφāĻĒ⧇āĻ•ā§āώāĻŋāĻ• āĻ¤ā§āϰ⧁āϟāĻŋ āĻļāϤāĻžāĻ‚āĻļ = (15.54/48.35×100)%
= 32.14%

As per the instructions of the assignment, you need to measure the area of marble with the help of the slide calipers art paper. You will also have to provide a mathematical explanation if you have 10% inaccuracy.

Before submitting your assignment solution, you need to be sincere in calculations. Please check and re-check before submission. Follow our website for the other Class 9 Physics Assignment Answer.

Final Words

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